Und noch ein paar Wurzeln

13. November 2007

Vereinfache:
a) \frac{x^2y^2}{ab^2}.{\left(\frac{a^{m+1}b^{2m+1}}{x^{2m}y^{2m+1}}\right)}^{\frac{1}{m}}

b) \sqrt[3]{\frac{a^2}{b}\cdot\sqrt{\frac{a^3}{b}}\cdot\sqrt[4]{\frac{b^3}{a^5}}}

c) \sqrt[5]{c^4 \cdot\sqrt[3]{c^2}}.\sqrt{c\cdot\sqrt[4]{c^3}}:\sqrt[24]{c^{41}}

d) \frac{\sqrt{64x^{10}y^{12}}}{\left(x^{\frac{10}{2}}y^{\frac{20}{3}}\right)^{\frac{3}{5}}} \; - \;\left(125x^5y^2\right)^{\frac{1}{3}} \cdot\left(5^6xy^4\right)^{\frac{1}{3}}

e) \left(3^6a^2b\right)^{\frac{1}{3}} \cdot \left(27a^4b^2\right)^{\frac{1}{3}} \; - \;\frac{\sqrt{81a^8b^4}}{\left(a^{\frac{10}{3}} b^{\frac{10}{6}}\right)^{\frac{3}{5}}}

f) \sqrt[4]{a\sqrt[6]{b^2\cdot a}}\,\cdot\,\sqrt[3]{\sqrt[8]{a^{11}\cdot b^{-1}}}\,\cdot\,\sqrt{b^2\cdot \sqrt[4]{a^2}}

Entry Filed under: Mathematik. Schlagworte: , , .

1 Comment Add your own

  • 1. alfredmuehlleitner  |  13. November 2007 at 23:28

    Lösungen:
    a) \sqrt[m]{ab{y}^{-1}}
    b) \sqrt[4]{a^3\cdot b^{-1}}
    c) \sqrt[10]{c}
    d) -117x^2y^2
    e) 18a^2b
    f) \sqrt[24]{b}

    Antworten

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